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(G)=3G^2-4G+6
We move all terms to the left:
(G)-(3G^2-4G+6)=0
We get rid of parentheses
-3G^2+G+4G-6=0
We add all the numbers together, and all the variables
-3G^2+5G-6=0
a = -3; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·(-3)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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